js得url参数方法
<form action="x.action" method="post">
<input type="hidden" name="from" id="from" value="" />
<input type="image" src="images/flash.jpg" />
</form>
<script language="javascript">
var url = window.location.search;
var i = url.indexOf("from=");
var j = url.indexOf("&",i+5);
var from="";
if(i>=0){
from = j>i?url.substring(i+5,j):url.substring(i+5);
}
document.getElementById("from").value= from;
</script>
lunzi
2007-08-16 18:24:23
评论:1
阅读:1262
引用:0
@2007-08-29 14:23:03 游客
var url = window.location.href;
