js得url参数方法

<form action="x.action" method="post">
<input type=
"hidden" name="from" id="from" value="" />
<input type=
"image" src="images/flash.jpg" />
</form>
<script language=
"javascript">
var url = window.location.search;
var i = url.indexOf(
"from=");
var j = url.indexOf(
"&",i+5);
var from=
"";
if(i>=0){
from = j>i?url.substring(i+5,j):url.substring(i+5);
}
document.getElementById(
"from").value= from;
</script>
lunzi   2007-08-16 18:24:23 评论:1   阅读:1262   引用:0
@2007-08-29 14:23:03  游客
var url = window.location.href;

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